Academic Level: Class 10 & 12 (Matric & Intermediate)  | 
Subject: Mathematics  | 
Institution: The Margaret’s Secondary School, Korangi, Karachi

Curriculum focus aligned with the Sindh Textbook Board, BSEK Matriculation, and BIEK Intermediate syllabus.

A complete mathematical tutorial on quadratic equations for matriculation and intermediate students, covering factorization, completing the square, formula derivation, and discriminant analysis.

Standard Form of a Quadratic Equation

A quadratic equation is a second-degree polynomial equation in a single variable x written in standard form as:

ax2 + bx + c = 0   (where a ≠ 0)

Where a, b, and c are real numerical constants. Quadratic equations arise constantly in kinematics (projectile motion), geometry (area calculations), and financial modeling.

Step-by-Step Derivation of the Quadratic Formula

The famous quadratic formula is derived using the method of completing the square on the standard form:

  1. Start with: ax2 + bx + c = 0
  2. Divide throughout by a:
    x2 + (b/a)x + (c/a) = 0
  3. Shift constant to the right side:
    x2 + (b/a)x = -(c/a)
  4. Add [b / (2a)]2 = b2 / (4a2) to both sides:
    x2 + (b/a)x + b2/(4a2) = b2/(4a2) – c/a
  5. Write left side as a perfect square:
    [x + b/(2a)]2 = (b2 – 4ac) / (4a2)
  6. Take the square root on both sides:
    x + b/(2a) = ± √(b2 – 4ac) / (2a)
  7. Subtract b/(2a) from both sides:
    x = [-b ± √(b2 – 4ac)] / (2a)

The Discriminant (Δ) and Nature of Roots

The quantity under the radical sign Δ = b2 – 4ac is called the discriminant. It dictates the character of the equation’s roots without explicitly solving:

  • Case 1: Δ > 0 and a perfect square: The roots are real, rational, and unequal.
  • Case 2: Δ > 0 and NOT a perfect square: The roots are real, irrational, and unequal (conjugate surds).
  • Case 3: Δ = 0: The roots are real, rational, and equal (repeated root: x = -b / 2a).
  • Case 4: Δ < 0: The roots are imaginary / complex conjugates.

Board Exam Problem Walkthrough

Problem: Solve for x: 2x2 – 7x + 3 = 0.

Solution:

Here a = 2, b = -7, c = 3.

Calculate Discriminant: Δ = (-7)2 – 4(2)(3) = 49 – 24 = 25 (Positive & perfect square).

Apply formula:

x = [-(-7) ± √25] / (2 × 2)

x = (7 ± 5) / 4

x1 = (7 + 5) / 4 = 12/4 = 3

x2 = (7 – 5) / 4 = 2/4 = 1/2

Solution Set = {3, 1/2}.

🎓 Key Academic Takeaways & Exam Strategies

  • Review key terminology, formulas, and definitions on a weekly basis.
  • Practice writing answers in neat bullet points to maximize marks in Board examinations.
  • Consult with your subject teachers at The Margaret’s Secondary School for additional past-paper guidance and laboratory demonstrations.

Frequently Asked Questions (FAQs)

Q: When should I use factorization versus the quadratic formula?

Ans: Factorization is faster when middle-term splitting is straightforward. The quadratic formula works universally for all quadratic equations, especially when roots involve surds or fractions.

Q: Can a quadratic equation have more than two roots?

Ans: No. According to the Fundamental Theorem of Algebra, an equation of degree n has exactly n roots.